0=0.0032x^2-0.32x+2

Solution for 0=0.0032x^2-0.32x+2 equation:

0=0.0032x^2-0.32x+2

We move all terms to the left:

0-(0.0032x^2-0.32x+2)=0

We add all the numbers together, and all the variables

-(0.0032x^2-0.32x+2)=0

We get rid of parentheses

-0.0032x^2+0.32x-2=0

a = -0.0032; b = 0.32; c = -2;
Δ = b2-4ac
Δ = 0.322-4·(-0.0032)·(-2)
Δ = 0.0768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.32)-\sqrt{0.0768}}{2*-0.0032}=\frac{-0.32-\sqrt{0.0768}}{-0.0064}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.32)+\sqrt{0.0768}}{2*-0.0032}=\frac{-0.32+\sqrt{0.0768}}{-0.0064}
$